Active Module: DILUTION
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Volumetric Dilution Simulator
M₁V₁ = M₂V₂: Adding solvent dilutes concentration, but preserves the total moles of solute.
Solve for:
Laboratory Dilution Sequence
1. Stock Solution
M₁ = 1 M
Concentrated
2. Pipette Transfer
V₁
Aliquot V₁ = 25 mL
0.025 mol transferred
3. Diluted Volumetric Flask
M₂ = 0.2 M
Final V₂ = 125 mL
+100 mL water added
Stock M₁:
Pipette V₁ (mL):
Target M₂:
Final V₂ (mL):
📐Step-by-Step Mathematical Derivation
Given ➔ Formula ➔ Solve1. Given Quantities:
• Stock Concentration (M₁): 1 M
• Stock Aliquot Volume (V₁): 25 mL
• Desired Diluted Concentration (M₂): 0.2 M
• Target Variable: Final Volume V₂
2. Governing Formula:
M₁ · V₁ = M₂ · V₂ ⟹ V₂ = (M₁ · V₁) / M₂
3. Substitute Values:
V₂ = (1 M × 25 mL) / 0.2 M
4. Calculated Result:
V₂ = 125 mL (Solvent water added = 100 mL)
5. Chemical Interpretation:Diluting 25 mL of 1.0 M stock solution with 100 mL of water yields 125 mL of 0.20 M solution. The 0.025 moles of solute remained constant throughout.
⚠️Conservation of Solute
When you add water to diluent, notice that the total number of dissolved solute particles (white dots) in the volumetric flask is exactly identical to the amount drawn by the pipette.
Only the spacing between particles increases, reducing the moles per unit volume.