Position: -8.00 m
Velocity: 3.00 m/s
Acceleration: 0.50 m/s²
Time: 0.00 s
t = 0.00 s/ 8.0s
Position vs. Time (x–t)[m]
dx/dt = v: 3.00
Velocity vs. Time (v–t)[m/s]
dv/dt = a: 0.50
Acceleration vs. Time (a–t)[m/s²]
Initial Position (x₀)-8.0 m
Initial Velocity (v₀)+3.0 m/s
Constant Acceleration (a)+0.5 m/s²
Duration (t_max)8.0 s
Live Kinematic Readout
Position (x)-8.00 m
Velocity (v)3.00 m/s
Displacement (Δx)0.00 m
Distance Traveled0.00 m
Governing Kinematic Equations
x(t) = x₀ + v₀t + ½at²
-8.00 = (-8) + (3)(0.00) + ½(0.5)(0.00)²
v(t) = v₀ + at
3.00 = (3) + (0.5)(0.00)
Physics Conceptual Challenge
Question 1 of 4What physical quantity is represented by the slope of a position-time (x–t) graph?
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