x = +1.00 mv = 0.00 m/sF = -25.0 N
💡 Drag the mass away from equilibrium to set initial displacement
t = 0.00 s/ 6.0s
Mechanical Energy Conservation
E_total = 12.50 JElastic Potential (U = ½kx²)12.50 J
Kinetic Energy (K)0.00 J
Total Energy (E)12.50 J
Displacement vs. Time (x–t)[m]
Velocity vs. Time (v–t) [Phase Lead 90°][m/s]
Oscillating Mass (m)1.0 kg
Spring Constant (k)25 N/m
Initial Amplitude (A)1.00 m
Harmonic Oscillation Measurements
Period (T = 2π√(m/k))1.26 s
Frequency (f = 1/T)0.80 Hz
Angular Freq (ω)5.00 rad/s
Restoring Force (F)-25.0 N
Max Speed (v_max)5.00 m/s
Total Energy (E)12.50 J
Hooke's Law & SHM Equations
Hooke's Law: F = -k · x
-25.0 N = -(25) · (1.00)
Natural Period: T = 2π√(m / k)
1.26 s = 2π√(1 / 25)
Physics Conceptual Challenge
Question 1 of 4At the equilibrium position (x = 0) of a horizontal mass-spring oscillator, which of the following is TRUE?
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